A charge of $5$ $5$ $C$ $C$ is passing through points A and B on a circuit. If the charge's electric potential changes from $28$ $28$ $J$ $J$ to $15$ $15$ $J$ $J$ , what is the voltage between points A and B?

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A charge of $5$ $5$ $C$ $C$ is passing through points A and B on a circuit. If the charge's electric potential changes from $28$ $28$ $J$ $J$ to $15$ $15$ $J$ $J$ , what is the voltage between points A and B?

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Answer 1 · 2018-04-12T23:44:02

Point A is at a voltage $2.6$ $2.6$ $V$ $V$ higher than point B. We would express this as $- 2.6$ $-2.6$ $V$ $V$ from A to B.

Explanation:

One volt is defined as one joule per coulomb, which we can write as $V = \frac{U}{C}$ $V=U/C$ where $V$ $V$ is the voltage difference, $U$ $U$ is the electric potential in joule and $Q$ $Q$ is the charge in coulomb.

In this case we're interested in the potential difference, so

$V=(DeltaU)/Q=(15-28)/5=(-13)/5=-2.6$ $V$

That is, point A is at a voltage $2.6$ $V$ higher than point B.

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A charge of $5$ $5$ $C$ $C$ is passing through points A and B on a circuit. If the charge's electric potential changes from $28$ $28$ $J$ $J$ to $15$ $15$ $J$ $J$ , what is the voltage between points A and B?

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Explanation:

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A charge of $5$ $5$ $C$ $C$ is passing through points A and B on a circuit. If the charge's electric potential changes from $28$ $28$ $J$ $J$ to $15$ $15$ $J$ $J$ , what is the voltage between points A and B?