A charge of $6 C$ $6 C$ is passing through points A and B on a circuit. If the charge's electric potential changes from $33 J$ $33 J$ to $9 J$ $9 J$ , what is the voltage between points A and B?

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Answer 1 · 2018-02-03T06:09:49

$4 V$ $4V$

Relationship between voltage ( $V$ $V$ ) and change in potential energy ( $δ U$ $delta U$ ) is given as,

$V = \frac{δ U}{q}$ $V= (delta U)/q$ (i.e the energy change for bringing a charge $q$ $q$ in between two points )

Given, $δ U = (33 - 9) J = 24 J$ $delta U = (33-9) J=24 J$ and, $q = 6 C$ $q=6C$

So, Volage is $(\frac{24}{6}) V = 4 V$ $(24/6) V=4V$

A charge of 6 C6C6 C is passing through points A and B on a circuit. If the charge's electric potential changes from 33 J33J33 J to 9 J9J9 J, what is the voltage between points A and B?