A charge of $6 C$ is passing through points A and B on a circuit. If the charge's electric potential changes from $42 J$ to $27 J$ , what is the voltage between points A and B?

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Answer 1 · 2017-02-22T09:16:06

The voltage is $=2.5V$

Work is done by the electric charge in going from $A$ to $B$

$DeltaW=q(V_B-V_A)$

$42-27=6*V_(AB)$

$V_(AB)=15/6=5/2=2.5V$

A charge of 6 C6 C is passing through points A and B on a circuit. If the charge's electric potential changes from 42 J42 J to 27 J27 J, what is the voltage between points A and B?