A charge of $6 C$ is passing through points A and B on a circuit. If the charge's electric potential changes from $27 J$ to $21 J$ , what is the voltage between points A and B?

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Answer 1 · 2016-10-10T17:52:15

1V

Porential or voltage is a measure of energy per unit charge. So the change in energy $Delta U$ is:

$Delta U = Delta V q$

$implies Delta V = (Delta U)/(q) = (27 - 21)/(6) = 1V$

A charge of 6 C6 C is passing through points A and B on a circuit. If the charge's electric potential changes from 27 J27 J to 21 J21 J, what is the voltage between points A and B?