A charge of $6 C$ is passing through points A and B on a circuit. If the charge's electric potential changes from $39 J$ to $6 J$ , what is the voltage between points A and B?

Question

1495 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-03-31T09:33:26

The voltage is $=5.5V$

The potential difference between the points $A$ and $B$ is $=U$

Voltage =Energy/Charge

$U=(DeltaE)/Q$

$DeltaE=39-6=33J$

The charge is $Q=6C$

$1 V=(1J)/C$

$U=33/6=5.5V$

A charge of 6 C6 C is passing through points A and B on a circuit. If the charge's electric potential changes from 39 J39 J to 6 J6 J, what is the voltage between points A and B?