A charge of $8 C$ $8 C$ is passing through points A and B on a circuit. If the charge's electric potential changes from $64 J$ $64 J$ to $8 J$ $8 J$ , what is the voltage between points A and B?

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Answer 1 · 2016-01-26T20:44:42

Electric potential is $\frac{Energy}{Charge}$ $("Energy")/("Charge")$ , and the potential difference is the change in potential.

$V = \frac{E}{Q}$ $V=E/Q$
$Delta V=(Delta E)/Q$
$Delta V=(8J-64J)/(8C)$
$Delta V=-7 V$

There is a 7V drop from A to B,

A charge of 8 C8C8 C is passing through points A and B on a circuit. If the charge's electric potential changes from 64 J64J64 J to 8 J8J8 J, what is the voltage between points A and B?