Question

A charge of `8 C` is passing through points A and B on a circuit. If the charge's electric potential changes from `42 J` to `16 J`, what is the voltage between points A and B?

Answer 1

I found `3.25V`

Explanation:

I would use the fact that `"Volt"="Joule"/"Coulomb"` so that:
at the initial position: `V_A=42/8=5.25V`
at the final position: `V_B=16/8=2V`
and between the two points `V_(AB)=5.25-2=3.25V`