A charge of $9 C$ is passing through points A and B on a circuit. If the charge's electric potential changes from $20 J$ to $11 J$ , what is the voltage between points A and B?

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Answer 1 · 2017-04-08T06:44:54

The voltage is $=1V$

The potential difference between the points $A$ and $B$ is $=U$

Voltage =Energy)/Charge

$U=(DeltaE)/Q$

$DeltaE=20-11=9J$

The charge is $Q=9C$

$1 V=(1J)/C$

$U=9/9=1V$

A charge of 9 C9 C is passing through points A and B on a circuit. If the charge's electric potential changes from 20 J20 J to 11 J11 J, what is the voltage between points A and B?