A charge of $9 C$ is passing through points A and B on a circuit. If the charge's electric potential changes from $15 J$ to $9 J$ , what is the voltage between points A and B?

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Answer 1 · 2016-03-22T19:56:51

$667mV$

Voltage or potential difference is defined as the work done per unit charge to move charges between the 2 points.

$therefore V=W/Q$

$=(15J-9J)/(9C)$

$=0.667V$ #

A charge of 9 C9 C is passing through points A and B on a circuit. If the charge's electric potential changes from 15 J15 J to 9 J9 J, what is the voltage between points A and B?