A charge of $9 C$ $9 C$ is passing through points A and B on a circuit. If the charge's electric potential changes from $27 J$ $27 J$ to $12 J$ $12 J$ , what is the voltage between points A and B?

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A charge of $9 C$ $9 C$ is passing through points A and B on a circuit. If the charge's electric potential changes from $27 J$ $27 J$ to $12 J$ $12 J$ , what is the voltage between points A and B?

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Answer 1 · 2016-01-28T05:06:23

-1.56volt

Explanation:

we know,
$V = \frac{W_{B} - W_{A}}{q}$ $V=(W_B-W_A)/q$
here,
$W_{B} = 12 j$ $W_B=12j$
$W_{A} = 27 j$ $W_A=27j$
$q = 9 C$ $q=9C$
then, by putting the values in the equation,
$V = \frac{12 j - 27 j}{9 C}$ $V=(12j-27j)/(9C)$
$= \frac{- 14 j}{9 C}$ $=(-14j)/(9C)$
$= - 1.56 j C^{- 1}$ $=-1.56jC^(-1)$
$= - 1.56 v o l t$ $=-1.56vol t$

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A charge of $9 C$ $9 C$ is passing through points A and B on a circuit. If the charge's electric potential changes from $27 J$ $27 J$ to $12 J$ $12 J$ , what is the voltage between points A and B?

1 Answer

Explanation:

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Science

Math

Humanities

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A charge of 9C9 C is passing through points A and B on a circuit. If the charge's electric potential changes from 27J27 J to 12J12 J, what is the voltage between points A and B?

1 Answer

Explanation:

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A charge of $9 C$ $9 C$ is passing through points A and B on a circuit. If the charge's electric potential changes from $27 J$ $27 J$ to $12 J$ $12 J$ , what is the voltage between points A and B?