A charge of 9 C is passing through points A and B on a circuit. If the charge's electric potential changes from 9 J to 3 J, what is the voltage between points A and B?

1 Answer
Apr 12, 2016

V_"AB"=-2/3 V

Explanation:

"data:"
q=9C
E_A=9J" potential energy for the point of A"
E_B=3J" potential energy for the point of B"

W=Delta E=E_B-E_A" work doing between two point"

W=3-9=-6J

W=q(V_B-V_A)

V_"AB"=V_B-V_A

W=q*V_"AB"

-6=9*V_"AB"

V_"AB"=-2/3 V