A charge of $9 C$ is passing through points A and B on a circuit. If the charge's electric potential changes from $9 J$ to $5 J$ , what is the voltage between points A and B?

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Answer 1 · 2017-04-06T06:08:44

The voltage is $=0.44V$

The potential difference between the points $A$ and $B$ is $=U$

Voltage =Energy/Charge

$U=(DeltaE)/Q$

$DeltaE=9-5=4J$

The charge is $Q=9C$

$1 V=(1J)/C$

$U=4/9=0.44V$

A charge of 9 C9 C is passing through points A and B on a circuit. If the charge's electric potential changes from 9 J9 J to 5 J5 J, what is the voltage between points A and B?