A charge of $9 C$ is passing through points A and B on a circuit. If the charge's electric potential changes from $29 J$ to $5 J$ , what is the voltage between points A and B?

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Answer 1 · 2017-07-23T12:56:53

THe voltage is $=2.67V$

The charge is $Q=It$

We apply Ohm's Law

$U=RI$

The power is

$P=UI$

And the energy is

$E=UIt$

$E=UQ$

and

$DeltaE=QDeltaU$

The voltage is

$DeltaU=(DeltaE)/Q=(29-5)/9=24/9=2.67V$

A charge of 9 C9 C is passing through points A and B on a circuit. If the charge's electric potential changes from 29 J29 J to 5 J5 J, what is the voltage between points A and B?