Question

A charge of `9 C` is passing through points A and B on a circuit. If the charge's electric potential changes from `29 J` to `2 J`, what is the voltage between points A and B?

Answer 1

`V_(AB)=-3V`

Explanation:

`"the voltage between two point is equal work doing by electrical forces between the point A and B."`
`"Work doing between two point is given as: "W=q(V_B-V_A)`
`V_B-V_A=V_(AB)`
`Delta W=q*V_(AB)`
`2-29=9*V_(AB)`
`V_(AB)=-27/9`
`V_(AB)=-3V`