A chord with a length of 1 runs from pi/12 to pi/8 radians on a circle. What is the area of the circle?

1 Answer

Area =183.609" "square units

Explanation:

From the data, an isosceles triangle can be formed with sides 1, r, and r. The central angle theta=pi/8-pi/12=pi/24.

We can split this isosceles triangle into 2 right triangles with hypotenuse r and acute angle 1/2 theta=pi/48 and opposite to this acute angle 1/2 theta=pi/48 is side with length 1/2.

We can now solve for r

csc (pi/48)=r/(1/2)

r=7.64489

and

Area=pir^2=pi(7.64489)^2=183.609

God bless....I hope the explanation is useful.