A chord with a length of $12$ runs from $pi/3$ to $pi/2$ radians on a circle. What is the area of the circle?

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Answer 1 · 2017-12-23T06:12:46

Area of the circle is 1688.3371

Chord length = 12
$theta = (pi/2) - (pi/3) = (pi) / 6$
$R = (c/2) / sin (theta/2) = (12/2)/sin ((pi)/12) = 23.1822$

Area of the circle = $pi R^2 = pi* 23.1822^2 = 1688.3371$

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A chord with a length of 12 12 runs from pi/3 pi/3 to pi/2 pi/2 radians on a circle. What is the area of the circle?