A chord with a length of $18$ runs from $pi/12$ to $pi/2$ radians on a circle. What is the area of the circle?

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Answer 1 · 2017-12-23T05:55:59

Area of the circle is 685.6567

Chord length = 18
$theta = (pi/2) - (pi/12) = (5pi) / 12$
$R = (c/2) / sin (theta/2) = (18/2)/sin ((5pi)/24) = 14.7841$

Area of the circle = $pi R^2 = pi* 14.7841^2 = 685.6567$

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A chord with a length of 18 18 runs from pi/12 pi/12 to pi/2 pi/2 radians on a circle. What is the area of the circle?