A chord with a length of $3$ runs from $pi/8$ to $pi/6$ radians on a circle. What is the area of the circle?

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Answer 1 · 2016-06-04T22:32:02

It is $22.93$ .

In a circle, the length of a chord is

$c=2rsin(theta/2)$

and so the radius is

$r=c/(2sin(theta/2)$

In our case theta is given by

$theta=pi/6-pi/8=pi/24$ .

then

$r=3/(2sin(pi/48))\approx22.93$

A chord with a length of 3 3 runs from pi/8 pi/8 to pi/6 pi/6 radians on a circle. What is the area of the circle?