A chord with a length of $8$ runs from $pi/12$ to $pi/8$ radians on a circle. What is the area of the circle?

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Answer 1 · 2017-12-23T06:16:30

Area of the circle is 11,750.9632

Chord length = 8
$theta = (pi/8) - (pi/12) = (pi) / 24$
$R = (c/2) / sin (theta/2) = (8/2)/sin ((pi)/48) = 61.1592$

Area of the circle = $pi R^2 = pi* 61.1592^2 = 11,750.9632$

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A chord with a length of 8 8 runs from pi/12 pi/12 to pi/8 pi/8 radians on a circle. What is the area of the circle?