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$a = ((F_{a} - \frac{c_{d} \cdot ρ_{h} \cdot A \cdot v^{2}}{2}) - m_{t} \cdot g_{r})$ $a=((F_a-(c_drho_hAv^2)/2)-m_tg_r)$ ?

So I have gotten this far...

$a = ((F_{a} - \frac{c_{d} \cdot ρ_{h} \cdot A \cdot v^{2}}{2}) - m_{t} \cdot g_{r})$ $a=((F_a-(c_drho_hAv^2)/2)-m_tg_r)$

This is based upon $F_{a} - \frac{F_{d} + F_{g}}{m} = a$ $F_a-(F_d+F_g)/m =a$

But $a$ $a$ is $\frac{d v}{d t}$ $(dv)/(dt)$

So this becomes a differential equation because the faster you go the harder it is to go faster.

How can one solve this

1 Answer

Aug 11, 2016

See https://socratic.org/questions/advanced-quadratic-drag-how-to-solve-2#274987

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