A gas absorbs a photon of 355 nm and emits at two wavelengths. If one of the emission is at 680 nm, the other is at - i) 1035 nm ii) 325 nm iii) 743 nm iv) 518 nm?
1 Answer
May 22, 2017
iii)
Explanation:
From Law of Conservation of energy, energy of absorbed photon must be equal to combined energy of two emitted photons.
#E_T = E_1+ E_2# .....(1)
where#E_1# is Energy of first emitted photon emitted and#E_2# is Energy of second emitted photon.
Energy
#E = (hc)/λ# .....(2)
where#h# is Planck's constant,#c# is velocity of light.
Inserting values from (2) in (1) we get
Substituting given values in (3) we get
