A man reached a speed of 372 km/h on his motorcycle. Suppose the man drives off a horizontal ramp at this speed and lands a horizontal distance of 40.0 m away from the edge of the ramp. What is the height of the ramp, neglecting air resistance?

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Answer 1 · 2015-11-26T18:08:49

#0.73"m"#

First we need to convert the speed into #"m/s"#:

#v=(372xx1000)/(60xx60)=103.3"m/s"#

The horizontal component of velocity is constant so we can say:

Time = distance/speed = #40/103.3=0.39"s"#

To get the vertical height we can use:

#s=1/2"g"t^2#

#:.s=0.5xx9.8xx0.39^2#

#s=0.73"m"#