A model train, with a mass of 2 kg, is moving on a circular track with a radius of 8 m. If the train's rate of revolution changes from 1/2 Hz to 2/7 Hz, by how much will the centripetal force applied by the tracks change by?

1 Answer
Mar 13, 2017

The change in centripetal force is =29N

Explanation:

The centripetal force is

F=mr omega^2

m=2kg

r=8m

Delta omega=(1/2-2/7)*2pi=3/7pirads^-1

The variation in centripetal force is

DeltaF=mr(Delta omega)^2

=2*8*(3/7pi)^2

=29N