Question

A model train with a mass of `3 kg` is moving along a track at `12 (cm)/s`. If the curvature of the track changes from a radius of `4 cm` to `18 cm`, by how much must the centripetal force applied by the tracks change?

Answer 1

=84000 #dyne

Explanation:

Let mass of train m =3kg = 3000 g
Velocity of train v = 12cm/s
Radius of first track `r_1=4cm`
Radius of Second track `r_2=18cm`
we know the centrifugal force =`(mv^2)/r`
Decrease in force in this case
`(mv^2)/r_1-(mv^2)/r_2`
`=(mv^2)*(1/r_1-1/r_2)=3*10^3*12^2(1/4-1/18)`
`=12000(9-2)=84000`dyne