A model train, with a mass of 3 kg, is moving on a circular track with a radius of 8 m. If the train's rate of revolution changes from 1/9 Hz to 1/7 Hz, by how much will the centripetal force applied by the tracks change by?

1 Answer
Apr 26, 2017

The centripetal force changes by =0.24N

Explanation:

The centripetal force is

F=mr omega^2

mass is m=3kg

radius r=8m

Delta omega=(1/7-1/9)*2pi=(2/63pi)rads^-1

The variation in centripetal force is

DeltaF=mr(Delta omega)^2

=3*8*(2/63pi)^2

=0.24N