A model train with a mass of $4 kg$ is moving along a track at $15 (cm)/s$ . If the curvature of the track changes from a radius of $35 cm$ to $12 cm$ , by how much must the centripetal force applied by the tracks change?

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Answer 1 · 2017-04-27T06:28:26

The centripetal force changes by $=0.493N$

The centripetal force is

$F=(mv^2)/r$

mass, $m=4kg$

speed, $v=0.15ms^-1$

radius, $=r$

The variation in centripetal force is

$DeltaF=F_2-F_1$

$F_1=mv^2/r_1=4*0.15^2/0.35=0.257N$

$F_2=mv^2/r_2=4*0.15^2/0.12=0.75N$

$DeltaF=0.75-0.257=0.493N$

A model train with a mass of 4 kg4 kg is moving along a track at 15 (cm)/s15 (cm)/s. If the curvature of the track changes from a radius of 35 cm35 cm to 12 cm12 cm, by how much must the centripetal force applied by the tracks change?