A model train with a mass of $4 kg$ is moving along a track at $18 (cm)/s$ . If the curvature of the track changes from a radius of $84 cm$ to $42 cm$ , by how much must the centripetal force applied by the tracks change?

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Answer 1 · 2018-03-22T08:42:34

The change in centripetal force is $=0.155N$

The centripetal force is

$vecF_C=(mv^2)/r*vecr$

The mass is of the train $m=4kg$

The velocity of the train is $v=0.18ms^-1$

The radii of the tracks are

$r_1=0.84m$

and

$r_2=0.42m$

The variation in the centripetal force is

$DeltaF=F_2-F_1$

The centripetal forces are

$||F_1||=4*0.18^2/0.84=0.154N$

$||F_2||=4*0.18^2/0.42=0.309N$

$DeltaF=F_1-F_2=0.154-0.309=-0.155N$

A model train with a mass of 4 kg4 kg is moving along a track at 18 (cm)/s18 (cm)/s. If the curvature of the track changes from a radius of 84 cm84 cm to 42 cm42 cm, by how much must the centripetal force applied by the tracks change?