A model train with a mass of $4 kg$ is moving along a track at $18 (cm)/s$ . If the curvature of the track changes from a radius of $25 cm$ to $15 cm$ , by how much must the centripetal force applied by the tracks change?

Question

1356 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-05-21T17:08:05

The change in centripetal force is $=0.34N$

The centripetal force is

$F=(mv^2)/r$

mass, $m=4kg$

speed, $v=0.18ms^-1$

radius, $=(r) m$

The variation in centripetal force is

$DeltaF=F_2-F_1$

$F_1=mv^2/r_1=4*0.18^2/0.25=0.52N$

$F_2=mv^2/r_2=4*0.18^2/0.15=0.86N$

$DeltaF=0.86-0.52=0.34N$

A model train with a mass of 4 kg4 kg is moving along a track at 18 (cm)/s18 (cm)/s. If the curvature of the track changes from a radius of 25 cm25 cm to 15 cm15 cm, by how much must the centripetal force applied by the tracks change?