Question

A model train with a mass of `4 kg` is moving along a track at `21 (cm)/s`. If the curvature of the track changes from a radius of `42 cm` to `45 cm`, by how much must the centripetal force applied by the tracks change?

Answer 1

The mass of the toy train `m =4kg`
The Velocity of the toy train `v =21cms^-1=0.21ms^-1`
The radius of first track = `r_1=42cm =0.42m`
The radius of second track = `r_2=45cm =0.45m`
So decrease in centripetal force for changing track is
`=mv^2(1/r_1-1/r_2)=4xx(0.21)^2xx(1/0.42-1/0.45)N~~.028N`