A model train with a mass of $4 kg$ is moving along a track at $6 (cm)/s$ . If the curvature of the track changes from a radius of $32 cm$ to $21 cm$ , by how much must the centripetal force applied by the tracks change?

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Answer 1 · 2017-07-20T05:52:34

The change in centripetal force is $=0.02357N$

The centripetal force is

$F=(mv^2)/r$

mass, $m=4kg$

speed, $v=0.06ms^-1$

radius, $=(r) m$

The variation in centripetal force is

$DeltaF=F_2-F_1$

$F_1=mv^2/r_1=4*0.06^2/0.32=0.045N$

$F_2=mv^2/r_2=4*0.06^2/0.21=0.06857N$

$DeltaF=0.06857-0.045=0.02357N$

A model train with a mass of 4 kg4 kg is moving along a track at 6 (cm)/s6 (cm)/s. If the curvature of the track changes from a radius of 32 cm32 cm to 21 cm21 cm, by how much must the centripetal force applied by the tracks change?