A model train with a mass of #4 kg# is moving along a track at #6 (cm)/s#. If the curvature of the track changes from a radius of #36 cm# to #45 cm#, by how much must the centripetal force applied by the tracks change?

1 Answer
Mar 8, 2017

The change in centripeta force is #=0.008N#

Explanation:

The centripetal force is

#F=(mv^2)/r#

#m=mass=4kg#

#v=0.06ms^-1#

The variation in centripetal force is

#DeltaF=F_2-F_1#

#F_1=4*0.06^2/0.36=0.04N#

#F_2=4*0.06^2/0.45=0.032N#

#DeltaF=0.04-0.032=0.008N#