A model train with a mass of $6 kg$ is moving along a track at $8 (cm)/s$ . If the curvature of the track changes from a radius of $3 cm$ to $15 cm$ , by how much must the centripetal force applied by the tracks change?

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Answer 1 · 2017-11-18T07:50:55

The change in centripetal force is $=1.024N$

The centripetal force is

$F=(mv^2)/r$

The mass, $m=(6)kg$

The speed, $v=(0.08)ms^-1$

The radius, $=(r) m$

$r_1=0.03m$

$r_2=0.15m$

The variation in centripetal force is

$DeltaF=F_2-F_1$

$F_1=mv^2/r_1=6*0.08^2/0.03=1.28N$

$F_2=mv^2/r_2=6*0.08^2/0.15=0.256N$

$DeltaF=F_1-F_2=1.28-0.256=1.024N$

A model train with a mass of 6 kg6 kg is moving along a track at 8 (cm)/s8 (cm)/s. If the curvature of the track changes from a radius of 3 cm3 cm to 15 cm15 cm, by how much must the centripetal force applied by the tracks change?