A model train with a mass of $8 k g$ $8 kg$ is moving along a track at $9 \frac{c m}{s}$ $9 (cm)/s$ . If the curvature of the track changes from a radius of $21 c m$ $21 cm$ to $72 c m$ $72 cm$ , by how much must the centripetal force applied by the tracks change?

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Answer 1 · 2016-05-08T12:07:49

Change in centripetal force
$Delta F=21,857.14286" "$ Dynes

Given data:
$m=8 " "$ kg
$v=9" ""cm/sec"$

$r_1=21" ""cm"$
$r_2=72" ""cm"$

For Centripetal Force

$F=(m*v^2)/r$

$F_1=(m*v^2)/r_1=(8000*9^2)/21=30857.14286$

$F_2=(m*v^2)/r_2=(8000*9^2)/72=9000$

$Delta F=F_1-F_2=21,857.14286" "$ Dynes

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A model train with a mass of 8 kg8kg8 kg is moving along a track at 9 (cm)/s9cms9 (cm)/s. If the curvature of the track changes from a radius of 21 cm21cm21 cm to 72 cm72cm72 cm, by how much must the centripetal force applied by the tracks change?