A model train, with a mass of $8 k g$ $8 kg$ , is moving on a circular track with a radius of $1 m$ $1 m$ . If the train's rate of revolution changes from $\frac{2}{5} H z$ $2/5 Hz$ to $\frac{5}{6} H z$ $5/6 Hz$ , by how much will the centripetal force applied by the tracks change by?

Question

1312 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-05-07T14:32:33

The centripetal force changes by $= 14.8 N$ $=14.8N$

The centripetal force is

$F = m r ω^{2}$ $F=mr omega^2$

mass is $m = 8 k g$ $m=8kg$

radius $r = 1 m$ $r=1m$

$Delta omega=(5/6-2/5)*2pi=(13/30pi)rads^-1$

The variation in centripetal force is

$DeltaF=mr(Delta omega)^2$

$=8*1*(13/30pi)^2$

$=14.8N$

A model train, with a mass of 8 kg8kg8 kg, is moving on a circular track with a radius of 1 m1m1 m. If the train's rate of revolution changes from 2/5 Hz25Hz2/5 Hz to 5/6 Hz56Hz5/6 Hz, by how much will the centripetal force applied by the tracks change by?