A particle is constrained to move in $Q_1$ , in a parabolic groove $y = x^2$ . It was at O, at t = 0 s. At time t s, its speeds in the directions Ox and Oy are 5 and 12 cm/s, respectively. How do you prove its direction makes $67^o22'49''$ with Ox?

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Answer 1 · 2017-02-18T15:11:06

See below.

Because of the constraint, the velocity vector is also the tangent vector. Therefore:

$theta = arctan (12/5) = 67.38^o$

A particle is constrained to move in Q_1Q_1, in a parabolic groove y = x^2 y = x^2. It was at O, at t = 0 s. At time t s, its speeds in the directions Ox and Oy are 5 and 12 cm/s, respectively. How do you prove its direction makes 67^o22'49''67^o22'49'' with Ox?