A projectile is shot at an angle of #pi/12 # and a velocity of # 4 m/s#. How far away will the projectile land?

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Answer 1 · 2017-04-21T08:22:17

The distance is #=0.82m#

Resolving in the vertical direction #uarr^+#

initial velocity is #u_y=vsintheta=4*sin(1/12pi)#

At the maximum height, #v=0#

We apply the equation of motion

#v=u+at#

to calculate the time to reach the greatest height

#0=4sin(1/12pi)-g*t#

#t=4/g*sin(1/12pi)#

#=0.106s#

Resolving in the horizontal direction #rarr^+#

To find the distance where the projectile will land, we apply the equation of motion

#s=u_x*2t#

#=4cos(1/12pi)*0.106*2#

#=0.82m#