A projectile is shot from the ground at a velocity of #27 m/s# at an angle of #(5pi)/12#. How long will it take for the projectile to land?

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Answer 1 · 2018-08-11T05:35:31

The time to land is #=5.32s#

Resolving in the vertical direction and applying the equation of motion

#s=ut+1/2at^2#

The distance travelled is #s=0#

The initial velocity is #u=27sin(5/12pi)#

The acceleration due to gravity is #a=g=9.8ms^-2#

#27sin(5/12pi)*t-1/2*9.8*t^2=0#

#t=0# which is the initial conditions

#t=(27sin(5/12pi))/(4.9)=5.32s#