Question

A projectile is shot from the ground at a velocity of `7 m/s` at an angle of `pi/3`. How long will it take for the projectile to land?

Answer 1

Data:-
Muzzle velocity`=`Initial velocity`=v_0=7m/s`

Angle`=theta=(pi)/3`

Time of flight`=T=??`
Sol:-
`T=(2v_0Sintheta)/g`

`implies T=(2*7sin((pi)/3))/9.8=(14*0.866)/9.8=12.124/9.8=1.2371s`

`implies T=1.2371s`