Question

A projectile is shot from the ground at a velocity of `86 m/s` at an angle of `pi/3`. How long will it take for the projectile to land?

Answer 1

Time = 14.5 s

Explanation:

We use the vertical direction to determine the time in the air.

`y = y_0 + v_(0y)t + 1/2a_yt^2`

In this case
`y=0`
`y_0=0`
`v_(0y)=82sin(pi/3)`
`a_y=-g`
So we have
`0=0+82tsin(pi/3)-1/2 g t^2`
So `t=0`
or `t=(2*82*sin(pi/3))/g=(2*82*sqrt3)/(2*9.8)=14.5 s`