A rectangular pool has an area of $750$ $ft^2$ . The length is 16 feet longer than the width. What are the dimensions of the pool?

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Answer 1 · 2018-04-06T12:13:46

$"Dimensions of the pool ' l = 36.53', w = 20.53'$

Given ; $l = w + 16, A = 750 sq.ft.$

$"Area of rectangle " A = l * w = (w + 16) * w$

$w^2 + 16w = 750$

$w^2 + 16w - 750 = 0$

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$w = (-16 +- sqrt(16^2 - 4 * (-750))) / 2$

$w = (-16 +- sqrt 3256)/ 2 = -8 +- sqrt 814 = -8 +- 28.53$

$w = 20.53, cancel(- 36.53) " invalid"$

$w = 20.53', l = 20.53 + 16 = 36.53'$

A rectangular pool has an area of 750750 ft^2ft^2. The length is 16 feet longer than the width. What are the dimensions of the pool?