A square has sides of length s+3. What is the area of the square?

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Answer 1 · 2016-12-01T02:22:52

$A = s^2 + 6s + 9$

The formula for the Area of a square is:

$A = l^2$ or $A = l*l$ Where $A$ is the area of the square and $l$ is the length of the side of a square.

For this problem we can substitute $s + 3$ for $l$ and solve:

$A = (s + 3)*(s + 3)$

$A = (s*s) + (3*s) + (3*s) + (3*3)$

$A = s^2 + (3 + 3)*s + 9$

$A = s^2 + 6s + 9$