Question

A vinegar solution has a `[OH^-] = 4.2*10^-10` `M` at 25°C. What is the `[H_3O^+]` of the vinegar solution?

Answer 1

`[H_3O^+]=2.38xx10^-5*mol*L^-1`

Explanation:

`[HO^-]=4.2xx10^-10`; `pOH=-log_10(4.2xx10^-10)=9.38`;

`pH=14-9.38=4.62`

And thus `[H_3O^+]=10^(-4.62)=2.38xx10^-5*mol*L^-1.`