An object with a mass of $12 k g$ $12 kg$ is revolving around a point at a distance of $12 m$ $12 m$ . If the object is making revolutions at a frequency of $14 H z$ $14 Hz$ , what is the centripetal force acting on the object?

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Answer 1 · 2017-05-14T12:40:28

The centripetal force is $= 1114238.86 N$ $=1114238.86N$

The centripetal force is

$F = m r ω^{2}$ $F=mr omega^2$

The mass is $m = 12 k g$ $m=12kg$

The radius is $r = 12 m$ $r=12m$

The angular velocity is $ω = 2 π f$ $omega=2pif$

Where the frequency is $= f H z$ $=f Hz$

So,

$ω = 2 \cdot π \cdot 14 = 28 π$ $omega=2*pi*14=28pi$

Therefore,

$F = 12 \cdot 12 \cdot {(28 π)}^{2} N$ $F=12*12*(28pi)^2 N$

$= 1114238.86 N$ $=1114238.86N$

An object with a mass of 12kg12 kg is revolving around a point at a distance of 12m12 m. If the object is making revolutions at a frequency of 14Hz14 Hz, what is the centripetal force acting on the object?