An object with a mass of $2$ $kg$ is revolving around a point at a distance of $7$ $m$ . If the object is making revolutions at a frequency of $13$ $Hz$ , what is the centripetal force acting on the object?

Question

1511 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-06-17T06:01:30

$F =mr\omega^2 =2xx7xx(13xx2\pi)^2 =93 405$ $N$

The centripetal force is given by:

$F=mr\omega^2$

where $r$ is the radius, $m$ is the mass and $\omega$ is the rotational frequency in $rads^-1$ .

To convert a frequency in $Hz$ to $rads^-1$ we multiply by $2\pi$ .

Therefore $F =mr\omega^2 =2xx7xx(13xx2\pi)^2 =93 405$ $N$

An object with a mass of 22 kg kg is revolving around a point at a distance of 77 mm. If the object is making revolutions at a frequency of 1313 Hz Hz, what is the centripetal force acting on the object?