An object with a mass of #4 kg# is hanging from a spring with a constant of #3 (kg)/s^2#. If the spring is stretched by # 5 m#, what is the net force on the object?

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Answer 1 · 2017-02-22T17:46:26

The net force on the object is #=27.2N# (acting downwards)

We resolve in the vertical direction #darr_+#

The weight acts downwards

#vecF_1=4g=4*9.8=39.2N#

According to Hooke's Law

#vecF_2=-kx#

#=-4*3=-12N#

The net force is

#vecF=vecF_1+vecF_2=39.2-12=27.2N#