An object with a mass of #5 kg# is hanging from a spring with a constant of #3 (kg)/s^2#. If the spring is stretched by #6 m#, what is the net force on the object?

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Answer 1 · 2017-05-03T06:28:48

The net force is #=31N#

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Mass of object #m=5kg#

The spring constant is #k=3kgs^-2#

Extension of the spring is #x=6m#

Resolving in the vertical direction #uarr^+#

The net force is #F=6*3-5g#

#=18-5g=-31N#

There is a net force of #31N# acting downwards