An object with a mass of #5 kg# is hanging from a spring with a constant of #3 (kg)/s^2#. If the spring is stretched by #7 m#, what is the net force on the object?

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Answer 1 · 2017-03-07T16:15:46

The net force on the object is #=28N# acting downwards

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Let's resolve in the vertical direction #uarr^+#

#F_1=kx=3*7=21N#

#F_2=-mg=-5g=-49N#

The net force is

#F=F_1+F_2=21-49=-28N#

The force is acting downwards,