An object with a mass of 55 kgkg is revolving around a point at a distance of 33 mm. If the object is making revolutions at a frequency of 1313 HzHz, what is the centripetal force acting on the object?

1 Answer
Feb 14, 2016

The centripetal force is given by F=momega^2rF=mω2r where mm is the mass (kg)(kg), omegaω is the frequency (rads^-1)(rads1) and rr is the radius (m)(m).

F=momega^2r=5*94.25^2*3=133246F=mω2r=594.2523=133246 NN

Explanation:

We need to convert the frequency: 1515 Hz=30pi=94.25Hz=30π=94.25 rads^-1#.