Question

An object with a mass of `6 kg` is hanging from a spring with a constant of `4 (kg)/s^2`. If the spring is stretched by `9 m`, what is the net force on the object?

Answer 1

What happens when you stretch the string and release, is that,the restoring force tries to pull the object upwards with the force `(F= K×x=4×9=36 N)`

So, net force acting on the object becomes `(mg-F)` i.e `(6×10-36) N` or `24 N` downwards.