Question

An object with a mass of `6 kg` is revolving around a point at a distance of `2 m`. If the object is making revolutions at a frequency of `9 Hz`, what is the centripetal force acting on the object?

Answer 1

I found `~~38kN`

Explanation:

We have that centripetal force is:
`F_c=ma_c=mv^2/r`
Where:
`v=("distance")/("time")=("circumference")/("period")=(2pir)/T`
With: `T=1/("frequency")=1/9`
So:
`v=2*3.14*2*9=113.04m/s`
So:
`F_c=6*(113.04)^2/2=38,334N`